Java reference

ArithmeticException

Thrown on an invalid arithmetic operation, such as integer division by zero.

Available since: Java 1.0

Syntax

public class ArithmeticException extends RuntimeException

Examples

Division by zero: integers and doubles:

void main() {
    try {
        int result = 10 / 0;
    } catch (ArithmeticException e) {
        IO.println(e.getMessage());
    }
    IO.println(10.0 / 0);
}

Output:

/ by zero
Infinity

Overflow with Math.addExact():

void main() {
    try {
        Math.addExact(Integer.MAX_VALUE, 1);
    } catch (ArithmeticException e) {
        IO.println(e.getMessage());
    }
}

Output:

integer overflow

Notes

Dividing a double by zero does not throw but gives Infinity or NaN. Ordinary int overflow is silent too; to get an exception use Math.addExact(), Math.multiplyExact(). It is better to check the divisor up front than to catch this exception.

Related recipes

In the tutorial

What exceptions are — Exceptions in Java — how a program reports an error, how to read a stack trace, common exceptions and the Throwable hierarchy.

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